whitespace

2 files changed, 5 insertions, 5 deletions

diff --git a/usr.bin/cal/README b/usr.bin/cal/README
index 638ac9dffb6..83051657ee2 100644
--- a/usr.bin/cal/README
+++ b/usr.bin/cal/README
@@ -10,13 +10,13 @@ that even if I was dumb enough to try.  From this we can easily calculate
 the day of week for any date.  The algorithm for a zero based day of week:
 
 	calculate the number of days in all prior years (year-1)*365
-	add the number of leap years (days?) since year 1 
+	add the number of leap years (days?) since year 1
 		(not including this year as that is covered later)
 	add the day number within the year
 		this compensates for the non-inclusive leap year
 		calculation
 	if the day in question occurs before the gregorian reformation
-		(3 sep 1752 for our purposes), then simply return 
+		(3 sep 1752 for our purposes), then simply return
 		(value so far - 1 + SATURDAY's value of 6) modulo 7.
 	if the day in question occurs during the reformation (3 sep 1752
 		to 13 sep 1752 inclusive) return THURSDAY. This is my
diff --git a/usr.bin/cal/cal.c b/usr.bin/cal/cal.c
index c37402dfd10..ea6c812d11e 100644
--- a/usr.bin/cal/cal.c
+++ b/usr.bin/cal/cal.c
@@ -1,4 +1,4 @@
-/*	$OpenBSD: cal.c,v 1.31 2022/12/04 23:50:47 cheloha Exp $	*/
+/*	$OpenBSD: cal.c,v 1.32 2024/08/18 19:58:35 deraadt Exp $	*/
 /*	$NetBSD: cal.c,v 1.6 1995/03/26 03:10:24 glass Exp $	*/
 
 /*
@@ -261,7 +261,7 @@ week(int day, int month, int year)
 	shift = 1;
 	if (yearday < firstsunday)
 		return (1);
-	if (firstweekday > THURSDAY - 1) 
+	if (firstweekday > THURSDAY - 1)
 		shift = 2;
 	return ((((yearday + 1) - (weekday - 1)) / 7) + shift);
 }
@@ -291,7 +291,7 @@ isoweek(int day, int month, int year)
 		return 53 - (g - s) / 5;
 	else if (n > 364 + s)
 		return 1;
-	else 
+	else
 		return n/7 + 1;
 }