/* $OpenBSD: md5crypt.c,v 1.15 2009/10/31 13:29:07 sobrado Exp $ */ /* * ---------------------------------------------------------------------------- * "THE BEER-WARE LICENSE" (Revision 42): * wrote this file. As long as you retain this notice you * can do whatever you want with this stuff. If we meet some day, and you think * this stuff is worth it, you can buy me a beer in return. Poul-Henning Kamp * ---------------------------------------------------------------------------- * * $FreeBSD: crypt.c,v 1.5 1996/10/14 08:34:02 phk Exp $ * */ #include #include #include #include #include static unsigned char itoa64[] = /* 0 ... 63 => ascii - 64 */ "./0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz"; static void to64(char *, u_int32_t, int); static void to64(char *s, u_int32_t v, int n) { while (--n >= 0) { *s++ = itoa64[v&0x3f]; v >>= 6; } } /* * UNIX password * * Use MD5 for what it is best at... */ char *md5crypt(const char *pw, const char *salt); char * md5crypt(const char *pw, const char *salt) { /* * This string is magic for this algorithm. Having * it this way, we can get get better later on */ static unsigned char *magic = (unsigned char *)"$1$"; static char passwd[120], *p; static const unsigned char *sp,*ep; unsigned char final[16]; int sl,pl,i; MD5_CTX ctx,ctx1; u_int32_t l; /* Refine the Salt first */ sp = (const unsigned char *)salt; /* If it starts with the magic string, then skip that */ if(!strncmp((const char *)sp,(const char *)magic,strlen((const char *)magic))) sp += strlen((const char *)magic); /* It stops at the first '$', max 8 chars */ for(ep=sp;*ep && *ep != '$' && ep < (sp+8);ep++) continue; /* get the length of the true salt */ sl = ep - sp; MD5Init(&ctx); /* The password first, since that is what is most unknown */ MD5Update(&ctx,(const unsigned char *)pw,strlen(pw)); /* Then our magic string */ MD5Update(&ctx,magic,strlen((const char *)magic)); /* Then the raw salt */ MD5Update(&ctx,sp,sl); /* Then just as many characters of the MD5(pw,salt,pw) */ MD5Init(&ctx1); MD5Update(&ctx1,(const unsigned char *)pw,strlen(pw)); MD5Update(&ctx1,sp,sl); MD5Update(&ctx1,(const unsigned char *)pw,strlen(pw)); MD5Final(final,&ctx1); for(pl = strlen(pw); pl > 0; pl -= 16) MD5Update(&ctx,final,pl>16 ? 16 : pl); /* Don't leave anything around in vm they could use. */ memset(final,0,sizeof final); /* Then something really weird... */ for (i = strlen(pw); i ; i >>= 1) if(i&1) MD5Update(&ctx, final, 1); else MD5Update(&ctx, (const unsigned char *)pw, 1); /* Now make the output string */ snprintf(passwd, sizeof(passwd), "%s%.*s$", (char *)magic, sl, (const char *)sp); MD5Final(final,&ctx); /* * and now, just to make sure things don't run too fast * On a 60 MHz Pentium this takes 34 msec, so you would * need 30 seconds to build a 1000 entry dictionary... */ for(i=0;i<1000;i++) { MD5Init(&ctx1); if(i & 1) MD5Update(&ctx1,(const unsigned char *)pw,strlen(pw)); else MD5Update(&ctx1,final,16); if(i % 3) MD5Update(&ctx1,sp,sl); if(i % 7) MD5Update(&ctx1,(const unsigned char *)pw,strlen(pw)); if(i & 1) MD5Update(&ctx1,final,16); else MD5Update(&ctx1,(const unsigned char *)pw,strlen(pw)); MD5Final(final,&ctx1); } p = passwd + strlen(passwd); l = (final[ 0]<<16) | (final[ 6]<<8) | final[12]; to64(p,l,4); p += 4; l = (final[ 1]<<16) | (final[ 7]<<8) | final[13]; to64(p,l,4); p += 4; l = (final[ 2]<<16) | (final[ 8]<<8) | final[14]; to64(p,l,4); p += 4; l = (final[ 3]<<16) | (final[ 9]<<8) | final[15]; to64(p,l,4); p += 4; l = (final[ 4]<<16) | (final[10]<<8) | final[ 5]; to64(p,l,4); p += 4; l = final[11] ; to64(p,l,2); p += 2; *p = '\0'; /* Don't leave anything around in vm they could use. */ memset(final, 0, sizeof final); return passwd; }