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/* $Id: des_locl.h,v 1.1 1995/12/14 06:52:44 tholo Exp $ */
/* Copyright (C) 1993 Eric Young - see README for more details */
#ifndef __des_locl_h
#define __des_locl_h
#include <sys/cdefs.h>
#include <stdio.h>
#include <memory.h>
#include <sys/types.h>
#include <unistd.h>
#include <sys/stat.h>
#include <fcntl.h>
#include <time.h>
#include "kerberosIV/des.h"
#define ITERATIONS 16
#define HALF_ITERATIONS 8
/* used in des_read and des_write */
#define MAXWRITE (1024*16)
#define BSIZE (MAXWRITE+4)
#define c2l(c,l) (l =((u_int32_t)(*((c)++))) , \
l|=((u_int32_t)(*((c)++)))<< 8, \
l|=((u_int32_t)(*((c)++)))<<16, \
l|=((u_int32_t)(*((c)++)))<<24)
/* NOTE - c is not incremented as per c2l */
#define c2ln(c,l1,l2,n) { \
c+=n; \
l1=l2=0; \
switch (n) { \
case 8: l2|=((u_int32_t)(*(--(c))))<<24; \
case 7: l2|=((u_int32_t)(*(--(c))))<<16; \
case 6: l2|=((u_int32_t)(*(--(c))))<< 8; \
case 5: l2|=((u_int32_t)(*(--(c)))); \
case 4: l1|=((u_int32_t)(*(--(c))))<<24; \
case 3: l1|=((u_int32_t)(*(--(c))))<<16; \
case 2: l1|=((u_int32_t)(*(--(c))))<< 8; \
case 1: l1|=((u_int32_t)(*(--(c)))); \
} \
}
#define l2c(l,c) (*((c)++)=(unsigned char)(((l) )&0xff), \
*((c)++)=(unsigned char)(((l)>> 8)&0xff), \
*((c)++)=(unsigned char)(((l)>>16)&0xff), \
*((c)++)=(unsigned char)(((l)>>24)&0xff))
/* replacements for htonl and ntohl since I have no idea what to do
* when faced with machines with 8 byte longs. */
#define HDRSIZE 4
#define n2l(c,l) (l =((u_int32_t)(*((c)++)))<<24, \
l|=((u_int32_t)(*((c)++)))<<16, \
l|=((u_int32_t)(*((c)++)))<< 8, \
l|=((u_int32_t)(*((c)++))))
#define l2n(l,c) (*((c)++)=(unsigned char)(((l)>>24)&0xff), \
*((c)++)=(unsigned char)(((l)>>16)&0xff), \
*((c)++)=(unsigned char)(((l)>> 8)&0xff), \
*((c)++)=(unsigned char)(((l) )&0xff))
/* NOTE - c is not incremented as per l2c */
#define l2cn(l1,l2,c,n) { \
c+=n; \
switch (n) { \
case 8: *(--(c))=(unsigned char)(((l2)>>24)&0xff); \
case 7: *(--(c))=(unsigned char)(((l2)>>16)&0xff); \
case 6: *(--(c))=(unsigned char)(((l2)>> 8)&0xff); \
case 5: *(--(c))=(unsigned char)(((l2) )&0xff); \
case 4: *(--(c))=(unsigned char)(((l1)>>24)&0xff); \
case 3: *(--(c))=(unsigned char)(((l1)>>16)&0xff); \
case 2: *(--(c))=(unsigned char)(((l1)>> 8)&0xff); \
case 1: *(--(c))=(unsigned char)(((l1) )&0xff); \
} \
}
/* The changes to this macro may help or hinder, depending on the
* compiler and the achitecture. gcc2 always seems to do well :-).
* Inspired by Dana How <how@isl.stanford.edu>
* DO NOT use the alternative version on machines with 8 byte longs. */
#ifdef ALT_ECB
#define D_ENCRYPT(L,R,S) \
u=((R^s[S ])<<2); \
t= R^s[S+1]; \
t=((t>>2)+(t<<30)); \
L^= \
*(u_int32_t *)(des_SP+0x0100+((t )&0xfc))+ \
*(u_int32_t *)(des_SP+0x0300+((t>> 8)&0xfc))+ \
*(u_int32_t *)(des_SP+0x0500+((t>>16)&0xfc))+ \
*(u_int32_t *)(des_SP+0x0700+((t>>24)&0xfc))+ \
*(u_int32_t *)(des_SP+ ((u )&0xfc))+ \
*(u_int32_t *)(des_SP+0x0200+((u>> 8)&0xfc))+ \
*(u_int32_t *)(des_SP+0x0400+((u>>16)&0xfc))+ \
*(u_int32_t *)(des_SP+0x0600+((u>>24)&0xfc));
#else /* original version */
#ifdef MSDOS
#define D_ENCRYPT(L,R,S) \
U.l=R^s[S+1]; \
T.s[0]=((U.s[0]>>4)|(U.s[1]<<12))&0x3f3f; \
T.s[1]=((U.s[1]>>4)|(U.s[0]<<12))&0x3f3f; \
U.l=(R^s[S ])&0x3f3f3f3f; \
L^= des_SPtrans[1][(T.c[0])]| \
des_SPtrans[3][(T.c[1])]| \
des_SPtrans[5][(T.c[2])]| \
des_SPtrans[7][(T.c[3])]| \
des_SPtrans[0][(U.c[0])]| \
des_SPtrans[2][(U.c[1])]| \
des_SPtrans[4][(U.c[2])]| \
des_SPtrans[6][(U.c[3])];
#else
#define D_ENCRYPT(L,R,S) \
u=(R^s[S ]); \
t=R^s[S+1]; \
t=((t>>4)+(t<<28)); \
L^= des_SPtrans[1][(t )&0x3f]| \
des_SPtrans[3][(t>> 8)&0x3f]| \
des_SPtrans[5][(t>>16)&0x3f]| \
des_SPtrans[7][(t>>24)&0x3f]| \
des_SPtrans[0][(u )&0x3f]| \
des_SPtrans[2][(u>> 8)&0x3f]| \
des_SPtrans[4][(u>>16)&0x3f]| \
des_SPtrans[6][(u>>24)&0x3f];
#endif
#endif
/* IP and FP
* The problem is more of a geometric problem that random bit fiddling.
0 1 2 3 4 5 6 7 62 54 46 38 30 22 14 6
8 9 10 11 12 13 14 15 60 52 44 36 28 20 12 4
16 17 18 19 20 21 22 23 58 50 42 34 26 18 10 2
24 25 26 27 28 29 30 31 to 56 48 40 32 24 16 8 0
32 33 34 35 36 37 38 39 63 55 47 39 31 23 15 7
40 41 42 43 44 45 46 47 61 53 45 37 29 21 13 5
48 49 50 51 52 53 54 55 59 51 43 35 27 19 11 3
56 57 58 59 60 61 62 63 57 49 41 33 25 17 9 1
The output has been subject to swaps of the form
0 1 -> 3 1 but the odd and even bits have been put into
2 3 2 0
different words. The main trick is to remember that
t=((l>>size)^r)&(mask);
r^=t;
l^=(t<<size);
can be used to swap and move bits between words.
So l = 0 1 2 3 r = 16 17 18 19
4 5 6 7 20 21 22 23
8 9 10 11 24 25 26 27
12 13 14 15 28 29 30 31
becomes (for size == 2 and mask == 0x3333)
t = 2^16 3^17 -- -- l = 0 1 16 17 r = 2 3 18 19
6^20 7^21 -- -- 4 5 20 21 6 7 22 23
10^24 11^25 -- -- 8 9 24 25 10 11 24 25
14^28 15^29 -- -- 12 13 28 29 14 15 28 29
Thanks for hints from Richard Outerbridge - he told me IP&FP
could be done in 15 xor, 10 shifts and 5 ands.
When I finally started to think of the problem in 2D
I first got ~42 operations without xors. When I remembered
how to use xors :-) I got it to its final state.
*/
#define PERM_OP(a,b,t,n,m) ((t)=((((a)>>(n))^(b))&(m)),\
(b)^=(t),\
(a)^=((t)<<(n)))
#endif /* __des_locl_h */
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